X^2+12=x-3

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Solution for X^2+12=x-3 equation: 



X^2+12=X-3

We move all terms to the left:

X^2+12-(X-3)=0

We get rid of parentheses

X^2-X+3+12=0

We add all the numbers together, and all the variables

X^2-1X+15=0

a = 1; b = -1; c = +15;
Δ = b2-4ac
Δ = -12-4·1·15
Δ = -59
Delta is less than zero, so there is no solution for the equation

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